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How do you solve #(3x-5)/2=4x#?

1 Answer

Nov 4, 2016

#x=-1

Explanation:

Given
#color(white)("XXX")(3x-5)/2=4x#

Multiply both sides by #2# to get rid of the fraction
#color(white)("XXX")3x-5=8x#

Subtract #3x# from both sides
#color(white)("XXX")-5=5x#

Divide both sides by #5#
#color(white)("XXX")-1=xcolor(white)("XX")"or (equivalently)"color(white)("XX")x=-1#

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