How do you solve $2(2-3x)=4(1-3/2x)$ ?

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Answer 1 · 2016-12-30T20:46:23

$x$ can have any value.

$2(2-3x)=4(1-3/2x)" "larr$ remove the brackets

$4-6x=4-6x" "larr$ both sides are identical

$6x-6x = 4-4$

$0=0$

This is a true statement but there is no $x$ left to solve for.

This is a special type of equation called an identity.

It will be true for any and every value of $x$

How do you solve 2(2-3x)=4(1-3/2x)2(2-3x)=4(1-3/2x)?