How do you solve #15+5(x-2)=7w+4#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer S.S · EZ as pi Oct 2, 2016 #x = (7w)/5 - 0.2# Explanation: Expand the brackets # 15 + 5x - 10 = 7w + 4# # 5x + 5 = 7w + 4# Divide both sides by #5# #x + 1 = (7w)/5 + 4/5# #x + 1 = (7w)/5 + 0.8# Take #5# from both sides #x = (7w)/5 - 0.2# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1298 views around the world You can reuse this answer Creative Commons License