Points (7 ,1 ) and (8 ,9 ) are (3 pi)/4 radians apart on a circle. What is the shortest arc length between the points?

1 Answer
Jul 19, 2016

color(blue)((3sqrt(65))/(4sqrt(2+sqrt(2)))

(This is pretty ugly; could someone check this please?)

Explanation:

Distance between (7,1) and (8,9) is given by the Pythagorean Theorem as
color(white)("XXX")sqrt(1^2+8^2)=sqrt(65)

To determine the arc length we will need to determine the radius of a circle with the given points at an angle of (3pi)/4 relative to the center of the circle.
enter image source here
(Note this diagram is not accurate).

If we let the radius of this circle be color(green)(r)
and denote
color(white)("XXX")(7,1) as P,
color(white)("XXX")(8,9) as Q,
color(white)("XXX")the center of the circle as C, and
color(white)("XXX")the point on the extension of PC to form a right angle with Q as S

then
Since
color(white)("XXX")/_PSQ=pi/2, and
color(white)("XXX")/_QCS=pi-(3pi)/4=pi/4
rarr
color(white)("XXX")/_CQS=pi/4 and
color(white)("XXX")abs(CS)=abs(QS)=r/sqrt(2)

Therefore
color(white)("XXX")abs(PS)=r+r/sqrt(2)=((sqrt(2)+1)/sqrt(2))r
and
color(white)("XXX")abs(PQ)=sqrt((r/sqrt(2))^2+(((sqrt(2)+1)/(sqrt(2)))r)^2)
color(white)("XXX")=(sqrt(2+sqrt(2)))r

But we previously determined that
color(white)("XXX")abs(PQ)=sqrt(65)
So
color(white)("XXX")r=sqrt(65)/(sqrt(2+sqrt(2))

The shortest arc length of an arc with radius color(green)(r) and an angle of (3pi)/4 is 3/4r

rArr shortest arc length is 3/4xxsqrt(65)/(sqrt(2+sqrt(2)))

color(white)("XXX")=(3sqrt(65))/(4sqrt(2+sqrt(2)))