A circle has a center at (7 ,6 ) and passes through (2 ,1 ). What is the length of an arc covering pi/12 radians on the circle?

1 Answer
juankentoy
Jan 25, 2016

1.8512 units

Explanation:

Using distance formula, solve for the distance between (7,6) and (2,1). That would be sqrt((7-2)^2 +(6-1)^2 equal to 5sqrt2 units. Since, arc length S = rtheta where r is the radius and theta is in radians. Multiplying: 5sqrt2 xx pi/12 = 1.8512 units

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