A circle has a center at $(7 ,6 )$ and passes through $(2 ,1 )$ . What is the length of an arc covering $pi$ radians on the circle?

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Answer 1 · 2016-02-17T01:10:59

length of arc $=5pisqrt2$

compute the radius r first using the two points $(7, 6)$ and $(2, 1)$

$r=sqrt((7-2)^2+(6-1)^2)=sqrt(5^2+5^2)=sqrt(2(25))=5sqrt2$

arc $s=r theta$

$s=(5sqrt2)*pi$

$s=5*pi*sqrt2$

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A circle has a center at (7 ,6 )(7 ,6 ) and passes through (2 ,1 )(2 ,1 ). What is the length of an arc covering pi pi radians on the circle?