A circle has a center at $(1 ,3 )$ and passes through $(2 ,4 )$ . What is the length of an arc covering $pi /4$ radians on the circle?

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Answer 1 · 2016-10-02T23:21:05

$s = (sqrt2pi)/4$

Compute the radius:

$r² = (2 - 1)² + (4 - 3)²$

$r = sqrt(2)$

The arc length ,s, is:

$s = rtheta$

$s = (sqrt2pi)/4$

A circle has a center at (1 ,3 )(1 ,3 ) and passes through (2 ,4 )(2 ,4 ). What is the length of an arc covering pi /4 pi /4 radians on the circle?