A circle has a center at $(3, 1)$ $(3 ,1 )$ and passes through $(2, 1)$ $(2 ,1 )$ . What is the length of an arc covering $\frac{π}{8}$ $pi/8$ radians on the circle?

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Answer 1 · 2016-03-10T08:42:40

length of arc $s = r \cdot θ = 1 \cdot \frac{π}{8} = \frac{π}{8} = 0.392699$ $s=r*theta=1*pi/8=pi/8=0.392699$

From the given data:
A circle has a center at (3,1) and passes through (2,1). What is the length of an arc covering π/8 radians on the circle?

We need the radius r to compute for the arc

$r = \sqrt{{(3 - 2)}^{2} + {(1 - 1)}^{2}} = \sqrt{1} = 1$ $r=sqrt((3-2)^2+(1-1)^2)=sqrt(1)=1$

$s = r \cdot θ = 1 \cdot \frac{π}{8} = \frac{π}{8} = 0.392699$ $s=r*theta=1*pi/8=pi/8=0.392699$

God bless...I hope the explanation is useful.

A circle has a center at (3,1)(3 ,1 ) and passes through (2,1)(2 ,1 ). What is the length of an arc covering π8pi/8 radians on the circle?