How do you solve #n-10=5/6n-7-1/3n#?

1 Answer
smendyka
Nov 7, 2016

#n = 6#

Explanation:

Step 1) Get all of the terms containing #n# over a common denominator by multiplying the term by the necessary for of #1#.
Step 2) Solve for #n# while keeping the equation balanced

#(6/6)n - 10 = (5/6)n - 7 - (2/2)(1/3)n#

#(6n)/6 -10 = (5n)/6 - 7 - (2n)/6#

#(6n)/6 - 10 = (3n)/6 - 7#

#(6n)/6 - 10 + 10 - (3n)/6 = (3n)/6 - 7 + 10 - (3n)/6#

#(6n)/6 - (3n)/6 = 3#

#(3n)/6 = 3#

#(6/3)((3n)/6) = (6/3)3#

#n = 6#

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