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How do you solve for x in #(a+b)x=c #?

1 Answer

Mar 7, 2018

See a solution process below:

Explanation:

Divide each side of the equation by #color(red)(a + b)# to solve for #x# while keeping the equation balanced:

#((a + b)x)/color(red)(a + b) = c/color(red)(a + b)#

#(color(red)(cancel(color(black)((a + b))))x)/cancel(color(red)(a + b)) = c/(a + b)#

#x = c/(a + b)#

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