How do you solve $4 x + 2 = 2 (x + 3) + 2 (x - 2)$ $4x+2=2(x+3)+2(x-2)$ ?

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How do you solve $4 x + 2 = 2 (x + 3) + 2 (x - 2)$ $4x+2=2(x+3)+2(x-2)$ ?

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Answer 1 · 2017-11-11T10:03:37

$infinite number of solutions$ $"infinite number of solutions"$

Explanation:

$distribute brackets on right side of equation$ $"distribute brackets on right side of equation"$

$4 x + 2 = 2 x + 6 + 2 x - 4$ $4x+2=2x+6+2x-4$

$\Rightarrow 4 x + 2 = 4 x + 2$ $rArr4x+2=4x+2$

$since both sides are identical then any value of x is$ $"since both sides are identical then any value of x is"$
$a solution$ $"a solution"$

$there are an infinite number of solutions$ $"there are an infinite number of solutions"$

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How do you solve $4 x + 2 = 2 (x + 3) + 2 (x - 2)$ $4x+2=2(x+3)+2(x-2)$ ?

1 Answer

Explanation:

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How do you solve 4x+2=2(x+3)+2(x-2)4x+2=2(x+3)+2(x−2)4x+2=2(x+3)+2(x-2)?

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How do you solve $4 x + 2 = 2 (x + 3) + 2 (x - 2)$ $4x+2=2(x+3)+2(x-2)$ ?