How do you solve $4d + 6= - 8+ 6d + 2$ ?

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Answer 1 · 2017-07-15T15:00:15

$d=6$

$4d+6=-8+6d+2$

Simplify the right side. $-8+2=-6$

$4d+6=6d-6$

Add $6$ to both sides.

$4d+6+6=6d-6+6$

$4d+12=6d$

Subtract $4d$ from both sides.

$4d-4d+12=6d-4d$

$12=2d$

Divide both sides by $2$ .

$12/2=(2d)/2$

$6=d$

Therefore, $d=6$

How do you solve 4d + 6= - 8+ 6d + 24d + 6= - 8+ 6d + 2?