How do you solve $4 d + 6 = - 8 + 6 d + 2$ $4d + 6= - 8+ 6d + 2$ ?

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Answer 1 · 2017-07-15T15:00:15

$d = 6$ $d=6$

$4 d + 6 = - 8 + 6 d + 2$ $4d+6=-8+6d+2$

Simplify the right side. $- 8 + 2 = - 6$ $-8+2=-6$

$4 d + 6 = 6 d - 6$ $4d+6=6d-6$

Add $6$ $6$ to both sides.

$4 d + 6 + 6 = 6 d - 6 + 6$ $4d+6+6=6d-6+6$

$4 d + 12 = 6 d$ $4d+12=6d$

Subtract $4 d$ $4d$ from both sides.

$4 d - 4 d + 12 = 6 d - 4 d$ $4d-4d+12=6d-4d$

$12 = 2 d$ $12=2d$

Divide both sides by $2$ $2$ .

$\frac{12}{2} = \frac{2 d}{2}$ $12/2=(2d)/2$

$6 = d$ $6=d$

Therefore, $d = 6$ $d=6$

How do you solve 4d+6=−8+6d+24d + 6= - 8+ 6d + 2?