How do you solve #-4(-d-4)=-4d+6(2d+6)#?
1 Answer
Jan 12, 2017
Explanation:
The first step is to distribute brackets on both sides of the equation.
#rArr4d+16=-4d+12d+36# simplifying right side.
#4d+16=8d+36# Collect terms in d, on the left side and numeric values on the right.
subtract 8d from both sides.
#4d-8d+16=cancel(8d)cancel(-8d)+36#
#rArr-4d+16=36# subtract 16 from both sides.
#-4dcancel(+16)cancel(-16)=36-16#
#rArr-4d=20# To solve for d, divide both sides by - 4
#(cancel(-4) d)/cancel(-4)=20/(-4)#
#rArrd=-5#
#color(blue)"As a check"#
#"left side " =-4(-(-5)-4)=-4xx1=-4#
#"right side " =(-4xx-5)+6(2xx(-5)+6)#
#=20+6(-10+6)=20+6(-4)=20-24=-4#
#"Thus both sides " =-4#
#rArrd=-5" is the solution"#
