How do you solve #4(1 - 2j) = 7(2j + 10)#?

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How do you solve #4(1 - 2j) = 7(2j + 10)#?

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Answer 1 · 2015-06-07T09:22:21

We are going to expand :

#4-8j=14j+70#
#4-70-8j=14j# ( we substract #70# on each side )
#-66-8j=14j#
#-66=14j+8j# ( we add #8j# on each side )
#-66=22j#
#(-66)/22=j# ( we divide by #22# on each side )
#j=-3#

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How do you solve #4(1 - 2j) = 7(2j + 10)#?

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