How do you solve $3x+82=x+2$ ?

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Answer 1 · 2018-06-25T20:59:35

$x=-40$

Subtract 82

$3x=x-80$

Subtract $x$

$2x=-80$

Divide by 2

$x=-40$

Answer 2 · 2018-06-25T21:12:26

$x=-40$

Let's see if we get our constants on the right and variables on the left. We can start by subtracting $x$ from both sides to get

$2x+82=2$

Next, let's get the $82$ on the right side by subtracting it from both sides.

$2x=-80$

Lastly, we divide both sides by $2$ to get

$x=-40$

Hope this helps!

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