How do you solve #-3 [x + 5 - 2( 3x - 10) - (4x - 10] = -2 [3x - 7( x + 2)]#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Don't Memorise Aug 23, 2015 #color(blue)(x=7# Explanation: #−3[x+5−color(blue)(2(3x−10)−(4x−10)]]=−2[3x−color(blue)(7(x+2)]]# #-3[x+5−6x+20 -4x +10]=−2[3x−7x-14]# #−3[x+5−10x+30]=−2[−4x-14]# #−3[-9x+35]=−2[−4x-14]# #27x-105=8x +28# #27x-8x=105 +28# #19x=133# #color(blue)(x=7# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 2158 views around the world You can reuse this answer Creative Commons License