How do you solve #3(2x-1)=9(x+3)#?

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Answer 1 · 2018-06-18T15:00:35

x = -10

Step 1, distribute the #3# and #9# into the parentheses:
#3(2x-1) -> 6x-3#

#9(x+3) -> 9x+27#

Step 2, combine like terms:
#quad6x-3 = 9x+27#
#-6x quadquad quad-6x#

#-3 = 3x+27#
#-27 quadquadquadquad -27#

#-30 = 3x#

Step 3, isolate the variable:
#-30 = 3x#

#-30/3 = (3x)/3#

#x = -10#