How do you solve #28+ 27p = 7( p - 22) + 34p#?

1 Answer
Jim G.
Dec 4, 2017

#p=13#

Explanation:

#"distribute the bracket on the right side of the equation"#

#28+27p=7p-154+34p#

#rArr28+27p=41p-154#

#"subtract 41p from both sides"#

#28+27p-41p=cancel(41p)cancel(-41p)-154#

#rArr28-14p=-154#

#"subtract 28 from both sides"#

#cancel(28)cancel(-28)-14p=-154-28#

#rArr-14p=-182#

#"divide both sides by "-14#

#(cancel(-14) p)/cancel(-14)=(-182)/(-14)#

#rArrp=13#

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