# How do you solve 2(3r + 1) = 2r?

Jun 25, 2015

$2 \left(3 r + 1\right) = 2 r$

Distribute the $2$ on the left side of the inequality.

$6 r + 2 = 2 r$

Subtract $2$ from both sides.

$6 r = 2 r - 2$

Subtract 2r from both sides.

$4 r = - 2$

Divide both sides by $4$.

$r = \frac{- 2}{4}$

$r = - \frac{1}{2}$