How do you solve #(-2(3-4m))/5=( 2m+1)/2#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Suren Abreu Oct 9, 2016 #m=2(5)/6# Explanation: #(-2(3-4m))/5 = (2m+1)/2# #(-6+8m)/5 = (2m+1)/2# #2(8m-6) = 5(2m+1)# #16m-12 = 10m+5# #16m-10m = 5+12# #6m = 17# #m=17/6# #m=2(5)/6# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1498 views around the world You can reuse this answer Creative Commons License