How do you solve #2 + 11b = 8b + 15#?

1 Answer
Jim G.
May 1, 2017

#b=13/3#

Explanation:

Collect terms in x on the left side of the equation and numeric values on the right side.

#"subtract 8b from both sides"#

#2+11b-8b=cancel(8b)cancel(-8b)+15#

#rArr2+3b=15#

#"subtract 2 from both sides"#

#cancel(2)cancel(-2)+3b=15-2#

#rArr3b=13#

#"divide both sides by 3"#

#(cancel(3) b)/cancel(3)=13/3#

#rArrb=13/3#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left side "=2+(11xx13/3)=6/3+143/3=149/3#

#"right side "=(8xx13/3)+15=104/3+45/3=149/3#

#rArrb=13/3" is the solution"#

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