How do you solve #14-1/5(j-10)=2/5(25+j)#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Gav May 5, 2018 #j=10# Explanation: #14-1/5j+1/5(10)=2/5(25)+2/5j# #14+2-1/5j=10+2/5j# Shift #j# to the left side and numbers to the right #-1/5j-2/5j=10-14-2# #-3/5j=-6# Divide both sides by #-3/5# #(-3/5j)/(-3/5)=(-6)/(-3/5)# #j=10# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 3079 views around the world You can reuse this answer Creative Commons License