How do you solve #1/2 (x-3) = 1/3 (2x+1)#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Kalyanam S. May 23, 2018 #color(orange)(x = -11# Explanation: #(1/2)(x-3) = (1/3) (2x +1)# Order of operations - BEDMAS #(1/2)*x - (1/2) *3 = (1/3)*2x +(1/3)*1#, removing braces. #x/2 - 3/2 = (2/3)x + 1/3#, multiplying. #(2/3)x - x/2 = -3/2 -1/3# #(4x-3x)/6 = (-9-2)/6#, taking L C M. #x/cancel6 = -11/cancel6#, simplifying. #color(orange)(x = -11# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 3366 views around the world You can reuse this answer Creative Commons License