How do you solve $3 (2 x - 1) = 9 (x + 3)$ $3(2x-1)=9(x+3)$ ?

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Answer 1 · 2018-06-18T15:00:35

x = -10

Step 1, distribute the $3$ $3$ and $9$ $9$ into the parentheses:
$3 (2 x - 1) \to 6 x - 3$ $3(2x-1) -> 6x-3$

$9 (x + 3) \to 9 x + 27$ $9(x+3) -> 9x+27$

Step 2, combine like terms:
$quad6x-3 = 9x+27$
$-6x quadquad quad-6x$

$-3 = 3x+27$
$-27 quadquadquadquad -27$

$-30 = 3x$

Step 3, isolate the variable:
$-30 = 3x$

$-30/3 = (3x)/3$

$x = -10$

How do you solve 3(2x-1)=9(x+3)3(2x−1)=9(x+3)3(2x-1)=9(x+3)?