How do you solve #7y+5 = 6y+11#?

2 Answers
Max · Shantelle
May 23, 2018

#y=6#

Explanation:

1) Get the variables to one side, do this by subtracting #6y# from both sides.
2) you now have #y+5=11#
3) now simplify by subtracting #5# from each side
4) #y=6#

Shantelle
May 23, 2018

#y = 6#

Explanation:

#7y+5=6y+11#

First, subtract #color(blue)6y# from both sides of the equation:
#7y + 5 quadcolor(blue)(-quad6y) = 6y + 11 quadcolor(blue)(-quad6y)#

#y + 5 = 11#

Now subtract #color(blue)5# from both sides:
#y + 5 quadcolor(blue)(-quad5) = 11 quadcolor(blue)(-quad5)#

Therefore,
#y = 6#

Hope this helps!

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