How do you solve #\frac { x - 2} { 5} = \frac { 2x - 1} { 11}#?

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Answer 1 · 2018-05-15T02:07:43

#x = 17#

Multiply the left-hand numerator #(x -2)# by #11#. Multiply the right-hand numerator #(2x-1)# by #5#.

So

#11x-22=10x -5#

#11x-22-10x=10x -5-10x#

#x - 22 = -5#

So

#x - 22+22 = -5+22#

# x= 17#

You can substitute #17# in to original equation to check:

# (17-2)/5 =(17xx2-1)/11 #

# 3=3#