How do you solve $-6( n + 2) + 15= - 3n - 9$ ?

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Answer 1 · 2018-05-08T22:24:23

n = 4

$-6(n + 2) + 15 = -3n - 9$

I expanded the brackets:
$-6(n + 2)$
$-6 xx n$ and $-6 xx 2$
$-6n - 12$

So now you have...
$-6n - 12 + 15 = -3n - 9$

Then you solve that...
$-6n - 12 + 15 = -3n - 9$

$-6n + 3 = -3n - 9$

$-6n + 3 + 3n = -9$
$-3n + 3 = -9$

$-3n = -9 - 3$
$-3n = -12$

$n = (-12)/-3$ (-12 divided by -3)
$n =4$

How do you solve -6( n + 2) + 15= - 3n - 9-6( n + 2) + 15= - 3n - 9?