How do you solve #7- 2n = n- 14#?

3 Answers
sophie · Stefan V.
Mar 26, 2018

#n=7#

Explanation:

#7-2n = n-14#

The first step is to move all of your variables, in this case #n#, to one side of the equation, and all constants (numbers without variables) to the other side:

#7-2n-n=-14#

#-2n-n=-14-7#

#-3n=-21#

You can then divide both sides of the equation by the coefficient (number in front of the variable):

#(-3n)/(-3)=(-21)/(-3)#

#n=7#

You can plug in your answer to check:

#7-2(7)=7-14#

#-7=-7#

Adrian C. · Stefan V.
Mar 26, 2018
  1. #7-2n = n-14#
  2. #7+14 = n +2n#
  3. #21 = 3n#
  4. #21/3 = (3n)/3#
  5. #7 = n#

Explanation:

  1. You have the original equation
  2. Move similar variables onto one side and numbers on the other
  3. Add the variables/numbers on each side
  4. Divide by the number associated with n to isolate for #n#
  5. You are left with #7#. #n = 7#
  6. You can check #7-2(7) = 7-14#
Humaira N. · Stefan V.
Mar 26, 2018

#n=7#

Explanation:

To solve this equation, first put the values with a variable on one side of the equals mark then the other numerical values on the other side. Be careful about the signs and solve the eq.as there is minus sign on both sides so they cancel out each other.

#7-2n=n-14#

#-2n-n=-14-7#

#-3n=-21#

#n= (-21)/-3#

#n=7#

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