How do you solve $3(1-3x)=2(-4x+7)$ ?

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Answer 1 · 2017-11-06T06:19:34

$x=-11$

First, expand both sides of the equation.

$3-9x=-8x+14$

Make sure that the variable, x, is only on one side of the equation. Add 9x to each side.

$3 -9x +9x = -8x +14 +9x$

$3 = 14 +x$

Subtract 14 from both sides.

$3-14=14+x-14$
$-11=x$

Check the solution:
$3(1-3[-11])=2(-4[-11]+7)$
$3(1--33)=2(44+7)$
$3(1+33)=2(44+7)$
$3(34)=2(51)$
$102=102$

How do you solve 3(1-3x)=2(-4x+7)3(1-3x)=2(-4x+7)?