How do you solve $5 y - 6 + y + 27 = 8 y + 30 - 5 y$ $5y - 6+ y + 27= 8y + 30- 5y$ ?

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How do you solve $5 y - 6 + y + 27 = 8 y + 30 - 5 y$ $5y - 6+ y + 27= 8y + 30- 5y$ ?

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Answer 1 · 2017-05-02T14:44:02

y=3

Explanation:

Collect like terms (if you don't know how, go here )

$5 y - 6 + y + 27 = 8 y + 30 - 5 y$ $5y-6+y+27=8y+30-5y$
$5 y + y + 27 - 6 = 8 y - 5 y + 30$ $5y+y+27-6=8y-5y+30$
$(5 + 1) y + 21 = (8 - 5) y + 30$ $(5+1)y+21=(8-5)y+30$
$6 y + 21 = 3 y + 30$ $6y+21=3y+30$
$6 y - 3 y = 30 - 21$ $6y-3y=30-21$
$3 y = 9$ $3y=9$
$y = \frac{9}{3}$ $y=9/3$
$y = 3$ $y=3$

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How do you solve $5 y - 6 + y + 27 = 8 y + 30 - 5 y$ $5y - 6+ y + 27= 8y + 30- 5y$ ?

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How do you solve 5y - 6+ y + 27= 8y + 30- 5y5y−6+y+27=8y+30−5y5y - 6+ y + 27= 8y + 30- 5y?

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How do you solve $5 y - 6 + y + 27 = 8 y + 30 - 5 y$ $5y - 6+ y + 27= 8y + 30- 5y$ ?