Applications of Radian Measure
Key Questions
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In physics you use radians to describe circular motion, in particular you use them to determine angular velocity,
omega .
You may be familiar with the concept of linear velocity given by the ratio of displacement over time, as:
v=(x_f-x_i)/t
wherex_f is the final position andx_i is the initial position (along a line).
Now, if you have a circular motion you use the final and initial ANGLES described during the motion to calculate velocity, as:
omega=(theta_f-theta_i)/t
Wheretheta is the angle in radians.
omega is angular velocity measured in rad/sec.
(Picture source: http://francesa.phy.cmich.edu/people/andy/physics110/book/chapters/chapter6.htm)Have a look to other rotational quantities you'll find a lot of ...radians!
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For any
theta , the length of the arc is given by the formula (if you work in radians, which you should:
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The area of the sector is given by the formula(theta r^2)/2 Why is this?
If you remember, the formula for the perimeter of a circle is2pir .
In radians, a full circle is2pi . So if the angletheta = 2pi , than the length of the arc (perimeter) =2pir . If we now replace2pi bytheta , we get the formulaS = rtheta If you remember, the formula for the area of a circle is
pir^2 .
If the angletheta = 2pi , than the length of the sector is equal to the area of a circle =pir^2 . We've said thattheta = 2pi , so that means thatpi = theta/2 .
If we now replacepi bytheta/2 , we get the formula for the area of a sector:theta/2r^2 -
Let's call the cord
AB and the centre of the circleC Then if you divide the cord in half at
M you get two equal, but mirrored trianglesDelta CMA andDelta CMB . These are both rectangular atM . (You should draw this yourself right now !).angle ACM is half the central angle that was given
(andangleBCM is the other half)Then
sin angle ACM=(AM)/(AC) ->AM=AC*sin angle ACM Since you know the radius
(AC) and the central angle (rememberangleACM= half of that), you just plug in these values to get an accurate result for half the chord (so don't forget to double it for your final answer) -
Answer:
See examples in explanation
Explanation:
Earth's day/night spin about it axis is with
angular speed =
2pi radian / 24-hour day.Earths revolution about Sun is owith
angular speed = #2pi) radian / 365.26-day year.
Rotors making electro-mechanical rotations have high angular
speeds of
kKpi radian / minute, k > 1,making thousands of rpm ( revolutions / minute ).
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