How do you find the complement and supplement of $64^{\circ}$ $64^circ$ ?

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Answer 1 · 2016-12-17T05:38:08

$26^{\circ}$ $26^@$
$116^{\circ}$ $116^@$

Complement of angle $64^{\circ}$ $64^@$ -->
90 - 64 = $26^{\circ}$ $26^@$
Supplement of $64^{\circ}$ $64^@$
180 - 64 = $116^{\circ}$ $116^@$

How do you find the complement and supplement of 64∘64^circ?