How does $sin x = 0$ $sinx=0$ equals π?

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How does $sin x = 0$ $sinx=0$ equals π?

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Answer 1 · 2015-02-03T00:02:16

The sine function equals $0$ $0$ for every multiple of $π \approx 3.14$ $pi~~3.14$

graph{sinx [0, 7, -1.2, 1.2]}

$π$ $pi$ radians is equal to $180^{0}$ $180^0$

The sine-function goes from $0$ $0$ to $1$ $1$ at $90^{0} = π / 2$ $90^0=pi//2$
And then back to $0$ $0$ at $180^{0} = π$ $180^0=pi$
Down to $- 1$ $-1$ at $270^{0} = 3 π / 2$ $270^0=3pi//2$
And up to $0$ $0$ again at $360^{0} = 2 π$ $360^0=2pi$

So it will be $0$ $0$ at every multiple of $π$ $pi$

Summary
$sin x = 0 \to x = k \cdot π$ $sin x=0 ->x=k*pi$ , with $k$ $k$ any whole number

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How does $sin x = 0$ $sinx=0$ equals π?

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