What is the equation of the circle with a center at #(-8 ,3 )# and a radius of #1 #?

1 Answer
Alan P.
Feb 19, 2016

#(x+8)^2+(y-3)^2=1#

Explanation:

The standard equation for a circle with center #(a,b)# and radius #r# is
#color(white)("XXX")(x-a)^2+(y-b)^2=r^2#

Using the given values results in the equation given in the "Answer"
(and this would be my preferred form)

...but,
you might have a teacher who wants this in "general polynomial standard form";
in this case you need to expand the terms, arrange them in descending order of degree with the polynomial equated to #0#:
#color(white)("XXX")x^2+y^2+16x-6y+72=0#

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