How do you write the complex number #z = −8# in trigonometric form?

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How do you write the complex number #z = −8# in trigonometric form?

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Answer 1 · 2016-02-26T15:51:25

#8(cos(pi/2)+isin(pi/2))#

Explanation:

#z=-8+0i#

In general #a+bi rArr r(cos(theta)+isin(theta))#
with #r=sqrt(a^2+b^2)#
and #theta ={(arctan(b/a) if a > 0),(pi/2 if a=0 and b > 0),(pi+arctan(b/a) if a < 0),(-pi/2 if a=0 and b < 0),("undefined" if a=0 and b=0):}#

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How do you write the complex number #z = −8# in trigonometric form?

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