How do you solve $x^2-3x=-10$ by completing the square?

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Answer 1 · 2015-05-28T19:54:46

$x^2-3x=-10$

$x^2-4x+4=-x-6$

$(x-2)^2=-x-6$

$x-2=sqrt(-x-6)$

No real solutions, because you can't have the square root of a negative number.

How do you solve x^2-3x=-10x^2-3x=-10 by completing the square?