How do you find the missing value to create a perfect square trinomial for $x^2+8x$ ?

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Answer 1 · 2018-07-06T19:01:58

$+16$

$(x+a)^2=x^2+2ax+a^2$

$"compare with "x^2+8x$

$2a=8rArra=8/2=4$

$"hence "x^2+8x+4^2=x^2+8xcolor(red)(+16)=(x+4)^2$

How do you find the missing value to create a perfect square trinomial for x^2+8xx^2+8x?