How do you solve $x^2+2x-3=0$ by completing the square?

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Answer 1 · 2015-05-05T11:22:22

$x^2+2x-3=0$

If $x^2+2x+a^2$ is a square then $a^2=1$

$x^2+2x+1 -1 -3 = 0$

$(x+1)^2 = 4$

$x+1 = +-sqrt(4)$

$x = -1 +-2$

$x=-3 " or " x=1$

How do you solve x^2+2x-3=0x^2+2x-3=0 by completing the square?