How do you solve #-14=2/5(9-2b)#?

1 Answer
EZ as pi
Aug 5, 2016

#b = 22#

Explanation:

While we could use the distributive property and multiply the #2/5# into the bracket, this is not the best approach, because we will just have to divide by #2/5# later.

Get rid of the #2/5# from the right side completely. #xx 5/2#

#-14 color(red)(xx5/2)=color(red)(5/2xx)2/5(9-2b)#

#cancel(-14)^(-7) color(red)(xx5/cancel2)=color(red)(cancel5/cancel2xx)cancel2/cancel5(9-2b)#

#-35 = 9-2b#

#2b= 9+35#
#2b = 44#
#b = 22#

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