How do you solve $(c+3)-2c-(1-3c)=2$ ?

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Answer 1 · 2018-05-13T05:26:04

$c=0$

1) Remove brackets as they are the same operation (addition / subtraction)

$c+3-2c-1-3c=2$

2) Simplify the coefficient of c

$-4c+3-1=2$

3) Simplify the number

$-4c+2=2$

4) Subtract two from both sides

$-4c=0$

5) Divide both sides by -4

$c=0$

How do you solve (c+3)-2c-(1-3c)=2(c+3)-2c-(1-3c)=2?