How do you solve $8 (1 + 7 m) + 6 = 14$ $8(1+7m)+6=14$ ?

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How do you solve $8 (1 + 7 m) + 6 = 14$ $8(1+7m)+6=14$ ?

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Answer 1 · 2018-05-01T19:02:11

$m$ $m$ = $0$ $0$

Explanation:

$8 (1 + 7 m) + 6 = 14$ $8(1 + 7m) + 6 = 14$

First, distribute $8$ $8$ to $(1 + 7 m)$ $(1 + 7m)$ , per the distributive property. (Multiply 1 by 8 and 7m by 8). You should now have:

$8 + 56 m + 6 = 14$ $8 + 56m + 6 = 14$

Combine like terms (8 and 6), and you should now have:

$14 + 56 m = 14$ $14 + 56m = 14$

Re-order the terms where $56 m$ $56m$ is first to help reduce confusion:

$56 m + 14 = 14$ $56m + 14 = 14$

Subtract accordingly.

$56 m = 0$ $56m = 0$

$m = 0$ $m = 0$

Sources and for clarification:
https://www.symbolab.com/solver/equation-calculator/8%5Cleft(1%2B7m%5Cright)%2B6%20%3D%2014
https://www.wyzant.com/resources/lessons/math/algebra/calculators/equation?equation=8(1+%2B+7m)+%2B+6+%3D+14

Answer 2 · 2018-05-01T19:02:27

$m = 0$ $m = 0$

Explanation:

$8 (1 + 7 m) + 6 = 14$ $8(1 + 7m) + 6 = 14$

Distribute the $8$ $8$ by multiplying it into the parentheses.

$8 + 56 m + 6 = 14$ $8 + 56m + 6 = 14$

Add the left side numbers without $m$ $m$ .

$56 m + 14 = 14$ $56m + 14 = 14$

Subtract both sides by $14$ $14$ .

$56 m + 14 - 14 = 14 - 14$ $56m + 14 - 14 = 14 - 14$

$56 m = 0$ $56m = 0$

Divide both sides by $56$ $56$ .

$\frac{56 m}{56} = \frac{0}{56}$ $(56m)/56 = 0/56$

$m = 0$ $m = 0$

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