How do you prove 1- [(cos^(2)x)/(1+sinx)]= sinx? Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer Alan P. Apr 15, 2015 By the Pythagorean Theorem cos^2(x) + sin^2(x) = 1 or cos^2(x) = 1-sin^2(x) So 1-[(cos^2(x))/(1+sin(x))] = 1- [(1-sin^2(x))/(1+sin(x))] =1 - [((1-sin(x))*(1+sin(x)))/(1+sin(x))] = 1- [1-sin(x)] = sin(x) Answer link Related questions What does it mean to prove a trigonometric identity? How do you prove \csc \theta \times \tan \theta = \sec \theta? How do you prove (1-\cos^2 x)(1+\cot^2 x) = 1? How do you show that 2 \sin x \cos x = \sin 2x? is true for (5pi)/6? How do you prove that sec xcot x = csc x? How do you prove that cos 2x(1 + tan 2x) = 1? How do you prove that (2sinx)/[secx(cos4x-sin4x)]=tan2x? How do you verify the identity: -cotx =(sin3x+sinx)/(cos3x-cosx)? How do you prove that (tanx+cosx)/(1+sinx)=secx? How do you prove the identity (sinx - cosx)/(sinx + cosx) = (2sin^2x-1)/(1+2sinxcosx)? See all questions in Proving Identities Impact of this question 29484 views around the world You can reuse this answer Creative Commons License