How do you prove that $\frac{tan x + cos x}{1 + sin x} = sec x$ $(tanx+cosx)/(1+sinx)=secx$ ?

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How do you prove that $\frac{tan x + cos x}{1 + sin x} = sec x$ $(tanx+cosx)/(1+sinx)=secx$ ?

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Answer 1 · 2015-02-14T13:32:15

I suspect that this identity doesn't work.
I tried to substitute an angle for $x$ $x$ and doesn't work (I used $x = \frac{π}{6}$ $x=pi/6$ , so you get $0.962 = 1.154$ $0.962=1.154$ ).
Maybe there is a typing error in it.

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How do you prove that $\frac{tan x + cos x}{1 + sin x} = sec x$ $(tanx+cosx)/(1+sinx)=secx$ ?

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How do you prove that $\frac{tan x + cos x}{1 + sin x} = sec x$ $(tanx+cosx)/(1+sinx)=secx$ ?