How do you graph #y=4 sin (2x -pi/3)#?

1 Answer
Alan P.
Apr 25, 2015

The graph of #y=4sin(2x-pi/3)#
will have the same form as the graph of #y=sin(theta)#
except
the amplitude will be #4# instead of #1#
and
the period will be #(2pi)/2 = pi#
and the sine wave will be shifted by #pi/6# to the right.
(since #sin(2x-pi/3) = sin(0) " when " x=pi/6" )"#
graph{4sin(2x-pi/3) [-10, 10, -5, 5]}

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