How do you graph y=4 sin (2x -pi/3)?

1 Answer
Alan P.
Apr 25, 2015

The graph of y=4sin(2x-pi/3)
will have the same form as the graph of y=sin(theta)
except
the amplitude will be 4 instead of 1
and
the period will be (2pi)/2 = pi
and the sine wave will be shifted by pi/6 to the right.
(since sin(2x-pi/3) = sin(0) " when " x=pi/6" )"
graph{4sin(2x-pi/3) [-10, 10, -5, 5]}

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