How do you draw a sketch of #y = 1 + cos (x - pi)#

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Answer 1 · 2018-07-13T11:58:57

As below

Standard form of cosine function is #y = A cos(Bx - C) + D#

Given #y = cos (x - pi) + 1#

#A = 1, B = 1, C = pi, D = 1#

#Amplitude = |A| = 1#

Period # = (2pi) / |B| = 2 pi#

Phase Shift # = -C / B = -pi / 1 = -pi#, #pi# to the LEFT

Vertical Shift #= 1#

graph{cos (x - pi) + 1 [-10, 10, -5, 5]}