How do you graph $x^2+y^2-1=0$ ?

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Answer 1 · 2016-12-29T11:39:03

$x^2+y^2-1=0$ is a circle with center at the origin and radius $1$

$x^2+y^2-1=0color(white)("XX")rArrcolor(white)("XX")x^2+y^2=1^2$

Any equation of the form $x^2+y^2=r^2$ is a circle with center at the origin i.e. at $(0,0)$ with a radius of $r$

How do you graph x^2+y^2-1=0x^2+y^2-1=0?