How do you graph #x^2+y^2-1=0#?

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Answer 1 · 2016-12-29T11:39:03

#x^2+y^2-1=0# is a circle with center at the origin and radius #1#

#x^2+y^2-1=0color(white)("XX")rArrcolor(white)("XX")x^2+y^2=1^2#

Any equation of the form #x^2+y^2=r^2# is a circle with center at the origin i.e. at #(0,0)# with a radius of #r#