How do you find the quotient of $(4 z^{3} + 1) \div 2 z$ $(4z^3+1)div2z$ ?

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Answer 1 · 2017-06-05T08:04:05

$= 2 z^{2} + \frac{1}{2 z}$ $=2z^2 +1/(2z)$

$(4 z^{3} + 1) \div 2 z = \frac{4 z^{3} + 1}{2 z}$ $(4z^3 +1)div2z " = "(4z^3 +1)/(2z )$

Write as 2 separate terms and simplify each:

$= \frac{4 z^{3}}{2 z} + \frac{1}{2 z}$ $=(4z^3)/(2z) +1/(2z)$

$= 2 z^{2} + \frac{1}{2 z}$ $=2z^2 +1/(2z)$

The second term is not divisible by $2 z$ $2z$ , so it becomes a remainder.

How do you find the quotient of (4z3+1)÷2z(4z^3+1)div2z?