How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#?

1 Answer
Gió
Dec 25, 2014

We can use the rule about division of rational expressions where you can change the division in a multiplication by flipping the second fraction (where, in your case, the second "fraction" can be written as #(x-5)/1#).

In our case you have:

#(x^2-25)/(x+3)-:(x-5)/1=(x^2-25)/(x+3)xx1/(x-5)#

We can now manipulate the numerator of the first fraction as:

#x^2-25=(x+5)*(x-5)#

Substituting and simplifying:

#((x+5)*(x-5))/(x+3)xx1/(x-5)=(x+5)/(x+3)#

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