How do you divide and reduce the expression to the lowest terms $2xy \-: \frac{2x^2}{y}$ ?

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Answer 1 · 2014-11-06T16:03:20

$2xy divide {2x^2}/y$

by rewriting as a multiplication,

$=2xy cdot {y}/{2x^2}={2xy^2}/{2x^2}$

by cancelling $2x$ ,

$={y^2}/{x}$

I hope that this was helpful.

How do you divide and reduce the expression to the lowest terms 2xy \-: \frac{2x^2}{y}2xy \-: \frac{2x^2}{y}?