How do you factor x^3+8y^3?

1 Answer
George C.
Sep 23, 2015

Use the sum of cubes identity a^3+b^3 = (a+b)(a^2-ab+b^2) to find:

x^3+8y^3 = (x+2y)(x^2-2xy+4y^2)

Explanation:

Use the sum of cubes identity with a = x and b = 2y:

x^3+8y^3 = x^3 + (2y)^3

= (x+2y)(x^2-x*2y+(2y)^2)

= (x+2y(x^2-2xy+4y^2)

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